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Therefore, 63 x + 72 x + 6 = 3. Let the original speed be x km/h. A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than its original speed.
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If it takes 3 hours. Let the original average speed of train be x km/hr. Express the total time as the sum of.
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We solve this equation to find x, the original average speed.
If it takes 3 hours to complete the total journey, what is its original average speed? A train travels at a certain average speed for a distance of 37 km and then travels a distance of 32km at an average speed of 6 km/h more than its original speed. We can set up the equation: A train travels at a certain average speed for a distance 63 km and then travels a distance of 72 km at an average speed of 6 km/hr more than the original speed, if it takes 3 hours to.
Hence, original speed of the train is 42 km/h. X63 + x+672 = 3. A train travels at a certain average speed for a distance of 63 km and then travels a distance of 72 km at an average speed of 6 km/h more than its original speed. Question a train travels at a certain average speed for a distanced of 54 km and then travels a distance of 63 km at an average speed of 6 km/hr more than the first speed.
If it takes 3 hours to complete the total journey, what is the original average speed?let original average speed = x km/h we know that, speed = 𝐷𝑖𝑠𝑡𝑎𝑛𝑐𝑒/𝑇𝑖𝑚𝑒 time = 𝑫𝒊𝒔𝒕𝒂𝒏𝒄𝒆/𝑺𝒑𝒆𝒆𝒅 train travelling.
If it takes 3 hours to complete. Original speed of train is 42 km/hr. But speed can't be negative.
